scatter plot with empty circle within loop

Question

I am looking for a simple and elegant way to make a scatter plot with multiple arrays, using empty circle as marker The colours should be chosen automatically. For example, I can make a plot with filled circle very easily:

a = {'1': np.random.rand(10), '2': np.random.rand(10), '3': np.random.rand(10)}
fig,ax = plt.subplots()
for y in ['2', '3']:
    ax.scatter(a[y], a['1'], label=y)

IF I want to use the kwargs facecolor="none", the markers just disappear. Somehow I need to automatically assign colors to edgecolor

BlackBear · Accepted Answer · 2020-06-16 13:58:45Z

2

Assign the edge color manually via C0, C1, etc., which follow the default palette:

a = {'1': np.random.rand(10), '2': np.random.rand(10), '3': np.random.rand(10)}
fig,ax = plt.subplots()
for i, y in enumerate(['2', '3']):
    ax.scatter(a[y], a['1'], label=y, facecolor='none', edgecolor=f'C{i}')

answered Jun 16, 2020 at 13:58

BlackBear

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5 Comments

Vinod Kumar Over a year ago

Thanks. But how do I access the default palette (f'C{i}')

BlackBear Over a year ago

@VinodKumar those colors work by default. You can control them e.g. with seaborn: seaborn.pydata.org/tutorial/color_palettes.html

Vinod Kumar Over a year ago

Perfect, Thanks a lot!

BlackBear Over a year ago

@VinodKumar you are welcome! If this answer satisfies you, please accept it.

Vinod Kumar Over a year ago

Done that! StackOverflow allows me to accept the answer after a time delay.

ywbaek · Accepted Answer · 2020-06-16 14:03:11Z

1

You can also use string o as a marker:

a = {'1': np.random.rand(10), '2': np.random.rand(10), '3': np.random.rand(10)}
fig,ax = plt.subplots()
for y in ['2', '3']:
    ax.scatter(a[y], a['1'], label=y, marker='$o$')

answered Jun 16, 2020 at 14:03

ywbaek

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2 Comments

Vinod Kumar Over a year ago

This is smart but only a way around. I have limited flexibility to choose markers in this way.

ywbaek Over a year ago

@VinodKumar Yeah I figured, but just wanted to give you another option =)

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