Sort a list of arrays using the sort of other array python

Question

I have two lists: a list of 2D-arrays and the time it was generated, which is an integer. They are of length N and both "equally disordered". So by using the indices to order the list 'time' I can order the list of 2D-arrays.

I would like to do something like:

ordered_list_of_arrays = np.asarray(disordered_list).argsort(np.asarray(time))
ordered_time = np.asarray(time).sort()

Another option would be to leave it as a list:

ordered_arrays = disordered_list[np.argsort(np.asarray(time))]
TypeError: only integer scalar arrays can be converted to a scalar index

By iterating np.argsort(time) I could sort my disordered_list but I would like to know if there is a better option for this or which are the best.

Thanks

li.sort(key=lambda x:time_list.index(x))

Shivam Jha
– Shivam Jha

2020-07-15 17:23:10 +00:00
Commented Jul 15, 2020 at 17:23 — Shivam Jha
– Shivam Jha, Commented Jul 15, 2020 at 17:23

Sabareesh · Accepted Answer · 2020-07-15 18:26:07Z

1

Create an index array and sort it based on time_list's value. Then use those indices to construct sorted versions of both arrays.

Code:

def sorted_lists(time_list, array_list):
    sorted_indices = sorted(range(len(time_list)), key=lambda i: time_list[i])
    sorted_time_list = [time_list[i] for i in sorted_indices]
    sorted_array_list = [array_list[i] for i in sorted_indices]
    return sorted_time_list, sorted_array_list

edited Jul 15, 2020 at 18:26

answered Jul 15, 2020 at 18:21

Sabareesh

7611 gold badge8 silver badges14 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Sort a list of arrays using the sort of other array python

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related