arr = [1]
arr[0] = arr.pop()
giving me IndexError: list assignment index out of range i don't understand why?
2 Answers
By calling arr.pop() it makes arr change to [], so after that if you try retrieving / chaging item at index 0 it will be out of range since its size is 0
Comments
The right-hand side of an assignment statement is evaluated before the left-hand side. So the list is empty when you try to assign at index 0.
You could rewrite your code roughly as:
arr = [1]
popped = arr.pop()
arr[0] = popped
pop'd from the list, now the list has zero elements, then you try to assign toarr[0], but since there is not arr[0], you get the index error.