PHP check element present in the array

Question

I have an array in the form of:

array(2) { [0]=> array(1) { ["positionID"]=> int(100) } [1]=> array(1) { ["positionID"]=> int(102) } }

I want to check 100 or 102 is contained in the array.

I tried code below, but it doesn't work. Can I get some help?

var_dump(in_array(102, $myArray));

Someone asked a very similar question to yours few hours ago, see this answer: stackoverflow.com/a/63331887/11430357 — catcon
– catcon, Commented Aug 10, 2020 at 1:18

zeterain · Accepted Answer · 2020-08-10 03:31:50Z

0

As @mario pointed out, you're going to want to use something like array_column:

var_dump(in_array(102, array_column($myArray, 'positionID")));

answered Aug 10, 2020 at 3:31

zeterain

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Prince Dorcis · Accepted Answer · 2020-08-10 03:39:50Z

0

Use

in_array(102, array_column($myArray, 'positionID'));

in_array checks the direct values of the array. So doing in_array(102, $myArray);, you are checking an integer (102) against the values of the array which are arrays.

answered Aug 10, 2020 at 3:39

Prince Dorcis

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