I have path = "dir1/dir2/dir3/file.py"
I need a way to get the full path to dir2 i.e. dir1/dir2.
something like findparent(path, 'dir2').
4 Answers
You can split the path by the target directory, take the first element from the list, and then add the target directory to the target path.
path = "dir1/dir2/dir3/file.py"
def findparent(path: str, dir_: str) -> str:
return path.split(dir_)[0] + dir_
print(findparent(path, 'dir2'))
# dir1/dir2
4 Comments
Tomergt45
I look for this exactly but without the need to define the function myself, if no one would mention a builtin function that does the same then I would mark this as the accepted answer
vmemmap
@Tomergt45 Sababa. Also, I added the
path: str to point the datatype that the function needs to get. And the -> str points the datatype that the function will return.Tomergt45
Ahla :) And I understood that but because this is a small function there isn't really a need to declare types
vmemmap
@Tomergt45 This is my writing style (';
If you use pathlib and the path actually exists:
path.resolve().parent
Just path.parent also works, purely syntactically, but has some caveats as mentioned in the docs.
To find one specific part of the parent hierarchy, you could iteratively call parent, or search path.parents for the name you need.
2 Comments
Tomergt45
.parent would just return the path to the parent directory, not to dir2, isn't it?
phipsgabler
Right, I missed that requirement initially.
Check this out! How to get the parent dir location
My favorite is
from pathlib import Path
Path(__file__).parent.parent.parent # ad infinitum
You can even write a loop to get to dir2, something like this..
from pathlib import Path
goal_dir = "dir2"
current_dir = Path(__file__)
for i in range(10):
if current_dir == goal_dir:
break
current_dir = current_dir.parent
Note: This solution is not the best, you might want to use a while-loop instead and check if there is actually a parent. If you are at root level and there is no parent, then it doesn't exist. But, assuming it exists and you don't have a tree deeper than 10 levels, this works.
Comments
Assuming your current work directory is at the same location as your dir1, you can do:
import os
os.path.abspath("dir1/dir2")
1 Comment
Tomergt45
My working directory is
dir3 so abspath('dir1/dir2') is not the answer
path.split('dir2')[0]?os.path.findparent, I forgot to mention it.