New to javascript and trying to use setTimeout [duplicate]

Question

I'm quite new to javascript and I want a the crickit.motor1.run(60) to get set to 0 after 2 seconds but it isn't working and I'm kinda out of options for what to do next. This is my code

forever(function() {
  if (crickit.touch1.touchRead() > 400) {
    light.setPixelColor(0, 0x00ffff)
    crickit.motor1.run(60);
  }

  pause(100)
})

function motorOff() {
  crickit.motor1.run(0);
}

forever(function() {
  if (crickit.motor1.run() = 60)
    setTimeout(motorOff() {

    }, 2000);
})

don't call motorOff function, just pass the name of the function to setTimeout --> setTimeout(motorOff, 2000); — Yousaf
– Yousaf, Commented Sep 5, 2020 at 12:56
crickit.motor1.run() = 60 should be using == or === for comparison. Singular = is for assignment — Nick Parsons
– Nick Parsons, Commented Sep 5, 2020 at 12:59

V.Volkov · Accepted Answer · 2020-09-05 12:58:01Z

0

These will work:

setTimeout( motorOff, 2000);

setTimeout( 'motorOff()', 2000);

setTimeout( function() { motorOff() }, 2000);

answered Sep 5, 2020 at 12:58

V.Volkov

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3 Comments

Snain Over a year ago

It still saying that I made a mistake somewhere in this part: forever(function () { if (crickit.motor1.run() == 60) setTimeout(function () { motorOff() }, 2000); }) and I have no idea what that would be

Mister Jojo Over a year ago

@Snain and there is no error message ?

V.Volkov Over a year ago

There is supposed to be if () {line1 line2} if there is no {}, JS adds only the first line to if

Alexandru DuDu · Accepted Answer · 2020-09-05 12:59:20Z

0

You have to use it like this: setTimeout(motorOff, 2000);
If you have a function that uses parameters, lets say motorOff(param) would accept 1 paramter, you have to use it like this:
setTimeout(motorOff, 2000, param);

answered Sep 5, 2020 at 12:59

Alexandru DuDu

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