I am currently studying Python String formatting. I have stucked on a problem
I have a string
s = "25Aug20"
I want to get the date month and year separately
sp_list = ['25', 'Aug', '20']
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4 Answers
You can use slicing:
sp_list = [s[:2], s[2:5], s[5:]]
If you want to get an actual datetime object, use .strptime():
from datetime import datetime
s = "25Aug20"
print(datetime.strptime(s, "%d%b%y"))
this will print
2020-08-25 00:00:00
2 Comments
Tiger Strom
Can you help me to convert it to 25-08-2020 ?
Selcuk
If you want to get a formatted string (i.e.
"25-08-2020") use mydatetime.strftime("%d-%m-%Y").You can use slicing, as already mentioned in another answer, but I will add that if there is any possibility that you might also need to process strings that use only a single character when dealing with single-digit dates, e.g. '5Aug20' (instead of '05Aug20' or ' 5Aug20'), then I suggest slicing relative to the end of the string to allow tolerance for this:
sp_list = [s[:-5], s[-5:-2], s[-2:]]
This should always work, provided only that the number of characters used for the year is always 2, and the number of characters used for the month is always 3.
Comments
You can also use Regex
Ex:
import re
s="25Aug20"
print(re.match(r"(\d+)([A-Za-z]+)(\d+)", s).groups())
# -->('25', 'Aug', '20')
Comments
You can achieve this without using datetime and slicing
s = "25Aug20"
month = ''.join(char for char in s if char.isalpha())
res = s.replace(month, f' {month} ').split()
print(res)
Output:
['25', 'Aug', '20']
