JavaScript array of objects contains every element of another array

Question

I have an array of objects (array1). I want to filter every element, that includes ALL of the tags ([1, 2, 3). So the result should be id 1. But i cannot make it work. The results i get are id 1, 2 ,4 and i do not understand why exactly it acts like this.

let array1 = [
  { id: 1, tags: [1, 2, 3] },
  { id: 2, tags: [2, 3] },
  { id: 3, tags: [0, 3] },
  { id: 4, tags: [1, 3] }
];

let tags = [1, 2, 3];

let includesAll = array1.filter((a1) =>
  a1.tags.every((tag) => tags.includes(tag))
);

console.log(includesAll);

trincot · Accepted Answer · 2020-09-16 21:25:17Z

3

You should do the opposite. Instead of verifying that every value in a1.tags is also in tags, you'll want to verify that every value in tags is also in a1.tags:

let includesAll = array1.filter((a1) =>
  tags.every((tag) => a1.tags.includes(tag))
);

let array1 = [
  { id: 1, tags: [1, 2, 3] },
  { id: 2, tags: [2, 3] },
  { id: 3, tags: [0, 3] },
  { id: 4, tags: [1, 3] }
];

let tags = [1, 2, 3];

let includesAll = array1.filter((a1) =>
  tags.every((tag) => a1.tags.includes(tag))
);

console.log(includesAll);

answered Sep 16, 2020 at 21:25

trincot

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