I would like to create a function that returns an array of multiples of a number within an array.
The first argument is a number and the second is the max number of the range.
For example:
getMultiples(5,24)
Output: [5,10,15,20]
*If the range is less than the first argument it should return an empty array.
getMultiples(5,0)
Output: []
Any idea how can I achieve this? Help
One of possible solutions:
const getMultiples = (f, t) =>
[...(Array(Math.floor(t / f)))]
.map((_, i) => f * (i + 1));
console.log(getMultiples(5, 24));
console.log(getMultiples(3, 11));
console.log(getMultiples(7, 1));Or extra one-liner:
const getMultiples = (f, t) =>
Array.from({ length: t / f }, (_, i) => f * (i + 1));
console.log(getMultiples(5, 24));Thanks @Rajesh
t / f to t. I am not sure what this does, but it works for me.The following code creates a generator function for the series up to limit; this is then spread across an array:
function* multiples(n, lim) {
if (lim < n) return []
let i = 1, r = 0
while ((r = n * i++) < lim) yield r
}
const getMultiples = (n, lim) => [...multiples(n, lim)]
console.log(getMultiples(5, 24))
console.log(getMultiples(5, 0))Alternative: create an array of the correct length, then use the index argument of map to populate the array:
const getMultiples = (n, lim) =>
lim < n
? []
: [...Array(~~(lim/n))].map((_,i) => ++i*n)
console.log(getMultiples(5, 24))
console.log(getMultiples(5, 0))Using a for-loop:
const getMultiples = (n, lim) => {
const arr = [], l = ~~(lim/n)
for(let x = 1; x <= l; x++)
arr.push(x*n)
return arr
}
console.log(getMultiples(5, 24))
console.log(getMultiples(5, 0))Using a for-of loop:
const getMultiples = (n, lim) => {
const arr = Array(~~(lim/n))
for(let x of arr.keys())
arr[x] = (x+1)*n
return arr
}
console.log(getMultiples(5, 24))
console.log(getMultiples(5, 0))Here an solution with while
function getMultiples(numb, sum) {
let count = 1;
let result = [];
while(numb * count <= sum) count = result.push(numb * count)
return result;
}
console.log(getMultiples(5, 23))
function getMultiples(num1, num2) {
var check = true;
var number = 0;
var arr = []
while (check == true) {
if (number <= num2) {
arr.push(number)
number += num1;
} else {
check = false
}
}
console.log(arr)
}
getMultiples(5, 24);I cant figure out on how to remove the 0 but I am sure you can figure that out
This should work:
getMultiples = (num, range) => {
if(range < num) {
return [];
}
const resultArr = [];
let result = 0;
let itr = 1;
while(result < range) {
result = num*itr;
if(result < range) {
resultArr.push(result);
}
itr++;
}
return resultArr;
}
console.log(getMultiples(5,24));
