Remove beginning of String with javascript/jquery

Question

I'm getting changing results from a method. It is everytime a String, but at the beginning of every String is written "String(xxx) "Text of String... ". The xxx depends on the number of characters inside of the String. I tried using regex to cut everything away before first appearance of " :

(result.replace(/^.+?(\") /, ''))

But I'm not sure if I used it correctly. I would also accept other approaches, which delete the beginning of the String in every case (independently of the length of the string).

Example:

return String: 'string(18) "This is an example"'

And I just want to get the String without the stuff at the beginning, so:

'This is an example'

But the return (and therefore the number in the parenthesis) can vary. I want to cut this out in every case.

You've put your space after the quote instead of before it var s = s.replace(/^.+? (\")/, '') — fdomn-m
– fdomn-m, Commented Oct 28, 2020 at 17:53
You'll also want to remove the " at the end .replace(/\"$/, "") — fdomn-m
– fdomn-m, Commented Oct 28, 2020 at 17:54
@pilchard nice option, but it might need to handle quotes in the middle (OP doesn't indicate if these are possible) — fdomn-m
– fdomn-m, Commented Oct 28, 2020 at 18:08

Rounin · Accepted Answer · 2020-10-28 18:28:47Z

1

You can achieve this with the following regex:

/.+\)\s\"(.*)\"/

As follows:

.+ - one or any number of characters
\)\s\" - until you reach ) "
(.*) - then capture everything
\" - until you reach the final "

Working Example:

const processString = (string) => {

  let processedString = string.replace(/.+\)\s\"(.*)\"/, '$1');

  console.log(processedString);
}


processString('string(18) "This is an example"');
processString('string(23) "This is another example"');
processString('string(25) "This is a "third" example"');

answered Oct 28, 2020 at 18:28

Rounin

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Ryszard Czech · Accepted Answer · 2020-10-28 22:24:08Z

Use

string.replace(/^.*? "|"$/g, '')

See proof.

Explanation

--------------------------------------------------------------------------------
  ^                        the beginning of the string
--------------------------------------------------------------------------------
  .*?                      any character except \n (0 or more times
                           (matching the least amount possible))
--------------------------------------------------------------------------------
   "                       ' "'
--------------------------------------------------------------------------------
 |                        OR
--------------------------------------------------------------------------------
  "                        '"'
--------------------------------------------------------------------------------
  $                        before an optional \n, and the end of the
                           string

JavaScript code:

const string = 'string(18) "This is an example"';
console.log(string.replace(/^.*? "|"$/g, ''));

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