PHP | If loop with multiple conditions

Question

I have a problem with an if loop with more than one condition inside I bring an example to understand:

for example let's say we have 3 fields in the same database table

one

two

three

each of these 3 fields has 3 states

empty

on hold

ready

I want to see a statement only when all 3 are up ready

    <?php if($collaboratore_abilitato['one'] === 'ready'|| $collaboratore_abilitato['two'] === 'ready' || $collaboratore_abilitato['three'] === 'ready') :?>

<!-- SHOW CODE -->

<?php else: ?>

<!-- SHOW ANTOHER CODE -->


    <?php endif; ?>

and

$collaboratore_abilitato

it s a paramater for a while

my problem is that when I activate the 3 parameter it shows me the contents of show code and not of show another code

I don't understand why it should show me show another code only when the 3 statements are verified in ready

|| means if any are ready, you may want && to check that they are all ready — Nigel Ren
– Nigel Ren, Commented Oct 30, 2020 at 17:12

Mike Foxtech · Accepted Answer · 2020-10-30 17:20:25Z

1

You should change || to && for check that they are all ready

<?php 
      if (
           $collaboratore_abilitato['one'] === 'ready' &&
           $collaboratore_abilitato['two'] === 'ready' &&
           $collaboratore_abilitato['three'] === 'ready' 
         ): 
?>

    <!-- SHOW CODE -->

<?php else: ?>

    <!-- SHOW ANTOHER CODE -->

<?php endif; ?>

answered Oct 30, 2020 at 17:20

Mike Foxtech

1,6511 gold badge8 silver badges7 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

PHP | If loop with multiple conditions

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related