I have a list in the form
lst = ['', 'how', '', 'are', 'you', '']
and want to convert it into
lst = ['how','are', 'you']
I have currently used the code list(filter(None,lst)) but no changes are returned. How can i remove the empty strings?
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1list(filter(None,lst)) works for me.norie– norie2021-04-27 14:06:14 +00:00Commented Apr 27, 2021 at 14:06
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1filter is not something that works "in place" you need to assign that back to lstJonSG– JonSG2021-04-27 14:14:05 +00:00Commented Apr 27, 2021 at 14:14
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4 Answers
Your code must works but an other solution is using lambdas:
lst = list(filter(lambda x: x != '', lst))
print(lst)
Output: ['how', 'are', 'you']
1 Comment
emmasa
Thanks @dgrana. My list had white spaces within the empty strings. I ddnt write it well on the question. lst = [' ', 'how', ' ', 'are', 'you', ' ' ]. Your solution works well. Thanks
Here you forgot to make the filter to this kinda thing:
lst = ['', 'how', '', 'are', 'you', '']
lst = list(filter(None, lst))
print(lst)
you define the list as list(filter(None, lst))
Comments
A simple and possible solution is the following:
lst = ['', 'how', '', 'are', 'you', '']
lst = [element for element in lst if element != '']
Now, lst is ['how', 'are', 'you']
2 Comments
JonSG
I love comprehensions. You might think about dropping the
!= "" as it is not technically needed.
pho
@JonSG it's helpful to mention why it's not technically needed, because it's not immediately obvious if you don't already know it -- because empty strings are falsy in python
Are you printing lst again? Your code works for me.
lst = ['', 'how', '', 'are', 'you', '']
lst = list(filter(None,lst))
print(lst)
outputs ['how', 'are', 'you']
1 Comment
emmasa
thanks for your replies. Actually my list is lst = [' ', 'how', ' ', 'are', 'you', ' ' ]. Notice the empty strings have a white space in between, and not as how i wrote in previously. filter function won't remove them. Should I assume that [' '] is not actually an empty string ?