how do I create a regex for this in urls.py?

Question

I want to create a regex that matches urls like this

filmslist?name=allaboutmymother?director=pedroalmodovar

in urlpatterns, I've put this:

path('api/filmslist\?name=?P<name>(.*)\?director=?P<director>(.*)', views.filmslist)

but it doesn't match. Thanks in advance

api/filmslist should be enough, everything from ? onwards is a querystring (GET parameters) — Abdul Aziz Barkat
– Abdul Aziz Barkat, Commented Apr 28, 2021 at 16:57
You have your named capture groups wrong, it is (?P<some_cool_name>...). That said, it should be filmslist\?name=(?P<name>.*)\?director=(?P<director>.*), see regex101.com/r/eLfjsX/1 — Jan
– Jan, Commented Apr 28, 2021 at 16:59
The qyerystring is not part of the path. You will need to parse this in the view itself. — willeM_ Van Onsem
– willeM_ Van Onsem, Commented Apr 28, 2021 at 17:02

Abdul Aziz Barkat · Accepted Answer · 2021-04-28 17:02:39Z

3

Everything after the first ? in a url is a querystring and is not involved in the pattern matching. So if your url is like filmslist?name=allaboutmymother?director=pedroalmodovar then your url pattern should be like:

path('api/filmslist', views.filmslist)

Now to get those parameters in your view you can do something like:

def filmslist(request):
    name = request.GET.get('name')
    director = request.GET.get('director')
    ...

Also as noted by @Code-Apprentice in their comment their should only be one ? in a url and the parameters need to be separated by an & so your url should be filmslist?name=allaboutmymother&director=pedroalmodovar

answered Apr 28, 2021 at 17:02

Abdul Aziz Barkat

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willeM_ Van Onsem · Accepted Answer · 2021-04-28 17:05:44Z

2

The qyery string is not part of the path. You will need to parse this in the view itself. In the view you can access parameters with request.GET which is a dictionary-like structure, so:

path('api/filmslist/', views.filmslist)

in the view you can then inspect the values with:

def filmslist(request):
    name = request.GET.get('name')
    director = request.GET.get('director')
    # …

If the parameter is not passed in the queryset, the corresponding name or director will be None.

answered Apr 28, 2021 at 17:05

willeM_ Van Onsem

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