I am building flutter router based on this doc: https://techblog.geekyants.com/navigation-20-routing-on-flutter-web.
The question I have is that how can I get the url parameter on initial load? e.g. I have the url http://localhost:8080?id=1234/#/user which points to the path /user defined in RouterDelegate. I am able to open the related screen which is for /user but where should I parse the url parameter id?
You can use the Uri class from dart:core
https://api.dartlang.org/apidocs/channels/stable/dartdoc-viewer/dart-core.Uri
ie: If url = http://localhost:8082/game.html?id=15&randomNumber=3.14
main() {
print(Uri.base.toString()); // http://localhost:8082/game.html?id=15&randomNumber=3.14
print(Uri.base.query); // id=15&randomNumber=3.14
print(Uri.base.queryParameters['randomNumber']); // 3.14
}
Whatever URL you enter in the browser it gets parsed in RouteInformationParser. In RouteInformationParser there is a method parseRouteInformation(),
in that method you will get the RouteInformation and you can parse the RouteInformation as
final uri = Uri.parse(routeInformation.location);
Then you can check the "id" here.
for eg -> let's say this is the route you have entered
http://localhost:8080?id=1234/#/user/2
final id = uri.pathSegments.elementAt(1).toString();
This will give the id = 2;
For reference you can check the parseRouteInformation method code inside
HomeRouteInformationParser (RouteInformationParser) class in the article that you have mentioned.
http://localhost:8080?id=1234/#/user/2, but after type in the browser, it becomes http://localhost:8080/#/user/2 and id parameter is wipped out.
final uri = Uri.parse(routeInformation.location); id = uri.queryParameters["id"]; (as mentioned in one of the answers here)id = uri.queryParameters["id"]; you will get id = "12345/user" and you can get id out of it -> uri.queryParameters["id"].split("/")[0]