Spliting a random string into half in python [duplicate]

Question

I have following problem: I want to split a string into half that always has different characters and always the same length. How would I do this since I can't specify a character with split().

import secrets

# generate string
string = secrets.token_hex(32)

# write string into file
write_string = open("string_file", "w").write(string)

# read and split string
read_string1 = open("string_file", "r").readline(32)
print(read_string1)

# i can only specify readline from 0-32 but how can I specify reading from 33-64 ?
read_string2 = open("string_file", "r").readline()
print(read_string2)

charles · Accepted Answer · 2021-05-12 19:01:01Z

0

How about :

randomStr = "sadfwoerowienwdfk"
halfway = int(len(randomStr)/2)
# prints first half followed by second half
print(randomStr[:halfway], randomStr[halfway:])

answered May 12, 2021 at 19:01

charles

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Comments

Dugbug · Accepted Answer · 2021-05-12 19:07:34Z

0

If you are looking for a one-liner:

string = "psjfdobhdcgspobhcpgdmj"


def split_halfway(string):
    return (string[:int(len(string) / 2)], string[int(len(string) / 2):])


print(split_halfway(string))

This function returns the first half followed by the second half

answered May 12, 2021 at 19:07

Dugbug

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Comments

MrLeeh · Accepted Answer · 2021-05-12 19:02:01Z

-1

try:

import secrets


string = "your_string"
print(string[0: int(len(string)/2)])

this'll just split it in half

edited May 12, 2021 at 19:02

MrLeeh

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answered May 12, 2021 at 19:00

N o b o d y

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1 Comment

N o b o d y Over a year ago

string = your_preferred_string

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