Problem with Runtime.getRuntime().exec()

Question

I have rooted my device, then in my application

Process p = Runtime.getRuntime().exec("su");

and it work fine, my application will be root mode. Then I try add wlan address space, but it doesn't work, when I check out in terminal, following error message is shown

 busybox ifconfig there is not a new wlan address space.

I try with following way:

Process p = Runtime.getRuntime().exec("su");
p = Runtime.getRuntime().exec("busybox ifconfig wlan0 add xxxxxxxxxxxx");
p.waitfor();

When I run my application, the toast shows that the app is root mode but there is not added wlan0.

Of course, if I write in terminal su, busybox ifconfig wlan0 add xxxxxxxx, it's works fine and there is a new wlan0 address space. — user760503
– user760503, Commented Aug 2, 2011 at 6:51

3c71 · Accepted Answer · 2012-05-08 12:39:36Z

1

The "su -c COMMAND" syntax is not really supported. For better portability, use something like this:

p = Runtime.getRuntime().exec("su");
stream = p.getOutputStream();
stream.write("busybox ifconfig wlan0 add xxxxxxxxxxxx");

The write() command doesn't exists as-is, but I'm sure you'll find how to write your stream to it, maybe encapsulating the output stream in a BufferedOutputWriter or so.

answered May 8, 2012 at 12:39

3c71

4,66135 silver badges46 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

John Dvorak · Accepted Answer · 2013-04-23 10:36:00Z

1

because the process that started with "busybox" is not the same one which started with "su". you should like this:

Process process = Runtime.getRuntime().exec("su");
OutputStream os = process.getOutputStream();
DataOutputStream dos = new DataOutputStream(os);
dos.writeBytes("busybox ifconfig wlan0 add xxxxxxxxxxxx" + "\n");
dos.flush();

edited Apr 23, 2013 at 10:36

John Dvorak

27.4k13 gold badges73 silver badges86 bronze badges

answered Apr 23, 2013 at 10:14

uncle long

115 bronze badges

Comments

Andy · Accepted Answer · 2011-08-02 09:20:36Z

0

That might be because when you run su, it launches one process. Then you run busybox ..., and it happens in another process, which is not started as a superuser.

Try something like

Process p = Runtime.getRuntime().exec(new String[] {"su", "-c", "busybox ifconfig wlan0 add xxxxxxxxxxxx"});

, i.e. executing it in a single command-line.

edited Aug 2, 2011 at 9:20

answered Aug 2, 2011 at 6:50

Andy

1,48417 silver badges33 bronze badges

8 Comments

user760503 Over a year ago

sorry, It dosen't works! no more toast that app is superuser and no wlan address space added.

Andy Over a year ago

@user760503: oh sorry, i forgot the -c switch. It should look like this: exec("su -c \"busybox ifconfig wlan0 add xxxxxxxxxxxx\"")

Andy Over a year ago

@user760503: man su tells that the syntax is su -c COMMAND.

user760503 Over a year ago

yes,I noticed after reading man pages. but it doen't work. I have tried out following way:

user760503 Over a year ago

exec("su -c \"busybox ifconfig wlan0 add xxxxxxxxxxxx\"") dosen't work and and following works only sudo part: String[] cmd = {"su","-c","busybox","ifconfig wlan0 add xxxxx"} sudo works now but no wlan has been added!

|

Collectives™ on Stack Overflow

Problem with Runtime.getRuntime().exec()

3 Answers 3

Comments

Comments

8 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

8 Comments

Your Answer

Sign up or log in

Post as a guest

Related