Re-order array of array of hash in ruby based on an array of key values

Question

I have an array of array of hash. For example,

arr =[[{:id=>61,:price=>20}, {:id=>61, :price=>23}, {:id=>61, :price=>60}],
     [{:id=>65, :price=>20}, {:id=>65, :price=>23}, {:id=>65, :price=>60}],
     [{:id=>69, :price=>20}, {:id=>69, :price=>33}, {:id=>69, :price=>80}]]

order_arr = [65,69,61]

How can I reorder the above array in a given order(based on 'order_arr') of key :id .

So, the result should be as below:

[[{:id=> 65, :price=>20}, {:id=>65, :price=>23}, {:id=>65, :price=>60}],
  [{:id=>69, :price=>20}, {:id=>69, :price=>33}, {:id=>69, :price=>80}],
  [{:id=>61,:price=>20}, {:id=>61, :price=>23}, {:id=>61, :price=>60}]]

Please help

nwnoll · Accepted Answer · 2021-09-08 12:19:20Z

2

I use the indices of your order_arr to sort the array of arrays with sort_by

arr =[[{:id=>61,:price=>20}, {:id=>61, :price=>23}, {:id=>61, :price=>60}],
     [{:id=>65, :price=>20}, {:id=>65, :price=>23}, {:id=>65, :price=>60}],
     [{:id=>69, :price=>20}, {:id=>69, :price=>33}, {:id=>69, :price=>80}]]


order_arr = [65,69,61]
sorted_arr = arr.sort_by { |ary| order_arr.index(ary.first[:id]) }

pp sorted_arr

edited Sep 8, 2021 at 12:19

answered Sep 8, 2021 at 12:11

nwnoll

1362 silver badges6 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Re-order array of array of hash in ruby based on an array of key values

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related