xml attribute parsing in scala

Question

I am trying to validate stuff against an xml schema. I am getting an input from user and checking to see if that value exist as a value for the name attribute. If it does i am returning true or if not false. Ive loaded the schema into a val and selected the nodes that i want like

val a = XML.load("schema.xml")
val nodes = (a \\ "Items")

Now a has the following

<Items name="name1" type="type1" />
<Items name="name2" type="type2" />
<Items name="name3" type="type3" />
<Items name="name4" type="type4" />

The user inputs the value name1

I tried doing

nodes.foreach(checkattr(_))

checkattr(val : elem)
{
  if(elem@name == userinput) { true } else { false }
}

But this is nt working and even if it does it seems the wrong way to do it as i want to return true or false only once for the entire traversal instead of the likes of waht i have specified above.

Any pointers would be useful for me.

Max A. · Accepted Answer · 2011-08-04 12:49:16Z

4

I believe what you want is something like:

scala> <foo baz="quux"/> \ "@baz"
res0: scala.xml.NodeSeq = quux

scala>

answered Aug 4, 2011 at 12:49

Max A.

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2 Comments

swordfish Over a year ago

what happens if there are multiple baz attributes, i tried it and it only returns a null array

Rex Kerr Over a year ago

@swordfish - Valid XML allows only a single attribute by a given name, doesn't it?

Nathaniel Ford · Accepted Answer · 2016-07-13 00:01:38Z

1

This is what I was searching for:

val isThere = dataItems \\ "@name" find { _.text == name }
if (isThere != None)
  return true
else
  false

Posted it as it might be useful for some one else too

edited Jul 13, 2016 at 0:01

Nathaniel Ford

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answered Aug 5, 2011 at 3:46

swordfish

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