Changing element in 2D numpy array to nan

Question

sample = np.array([[-1, 1, -1, 1], [-1, 2, -1, 2], [-1, 3, 3, 3] ,[-1, 4, 4, 4], [-1, 5, 5, 5], [6, 6, 6, -1], [7, 7, 7, -1], [8, 8, -1, -1], [9, 9, -1, -1]])
float_sample = sample.astype(np.float64)

for row in float_sample:
    for ele in row:
        if (ele == -1.):
            float_sample[row][ele] = np.nan

I am trying to iterate through a 2D numpy array and whenever I see -1, convert it to NaN, np.nan. But whenever I try to do it doing the iteration I have above I get the following error message:

"Arrays used as indices must be of integer (or boolean) type"

How to I fix it so that I can iterate through a 2D numpy array of type float and whenever it finds a -1, convert it to NaN? I am doing this so that I can take the median of each column but you can't do that using masked arrays so I am stuck trying to do it with a normal numpy array.

Dani Mesejo · Accepted Answer · 2021-11-11 21:39:14Z

2

Use numpy's boolean indexing:

import numpy as np

sample = np.array(
    [[-1, 1, -1, 1], [-1, 2, -1, 2], [-1, 3, 3, 3], [-1, 4, 4, 4], [-1, 5, 5, 5], [6, 6, 6, -1], [7, 7, 7, -1],
     [8, 8, -1, -1], [9, 9, -1, -1]])

float_sample = sample.astype(np.float64)
float_sample[sample == -1] = np.nan
print(float_sample)

Output

[[nan  1. nan  1.]
 [nan  2. nan  2.]
 [nan  3.  3.  3.]
 [nan  4.  4.  4.]
 [nan  5.  5.  5.]
 [ 6.  6.  6. nan]
 [ 7.  7.  7. nan]
 [ 8.  8. nan nan]
 [ 9.  9. nan nan]]

As a side note the problem is that you are using the row to index in:

float_sample[row][ele] = np.nan

and row is an array of floats.

answered Nov 11, 2021 at 21:39

Dani Mesejo

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Comments

mozway · Accepted Answer · 2021-11-11 21:40:04Z

0

Do not iterate (it is slow), use vectorial operations instead, like np.where:

float_sample = np.where(sample == -1, np.nan, sample)

output:

array([[nan,  1., nan,  1.],
       [nan,  2., nan,  2.],
       [nan,  3.,  3.,  3.],
       [nan,  4.,  4.,  4.],
       [nan,  5.,  5.,  5.],
       [ 6.,  6.,  6., nan],
       [ 7.,  7.,  7., nan],
       [ 8.,  8., nan, nan],
       [ 9.,  9., nan, nan]])

answered Nov 11, 2021 at 21:40

mozway

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Comments

Thekingis007 · Accepted Answer · 2021-11-11 21:43:39Z

0

Try this one:

sample = np.array([[-1, 1, -1, 1], [-1, 2, -1, 2], [-1, 3, 3, 3] ,[-1, 4, 4, 4], [-1, 5, 5, 5], [6, 6, 6, -1], [7, 7, 7, -1], [8, 8, -1, -1], [9, 9, -1, -1]])
float_sample = sample.astype(np.float64)

for row in float_sample:
    for i in range(len(row)):
        if (row[i] == -1.):
            row[i] = np.nan

Output:

[[nan  1. nan  1.]
 [nan  2. nan  2.]
 [nan  3.  3.  3.]
 [nan  4.  4.  4.]
 [nan  5.  5.  5.]
 [ 6.  6.  6. nan]
 [ 7.  7.  7. nan]
 [ 8.  8. nan nan]
 [ 9.  9. nan nan]]

answered Nov 11, 2021 at 21:43

Thekingis007

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