Having trouble with echoing HTML in php script

Question

I am trying to make a form that show users name and I am having a little trouble with this part. The ' ' and " " marks dont quite work how they are supposed to. Im trying to echo the options in drop down menu and some how the $wholenames and the last " sign appear in the wrong part of the page. Could someone please tell me what is the correct way of doing this?

Thanks

 echo' "<option>'; echo $wholenames; echo'</option>"';

Actually I had looked it wrong it is a little bit more complex. Below you can see the code. The whole dropdown menu does not appear. The wholenames integer appears, but the menu does not...

echo'

      <label for="addusertogroup">Add user  to an existing group:</label>
      <select name="addusertogroup" id="addusertogroup">
      ';  if(mysql_num_rows($userresult)) 
        { 
            while($row2 = mysql_fetch_assoc($userresult)) 
            { 

            $wholename = array("$row2[f_name] $row2[s_name]");

                foreach ($wholename as $wholenames) {   

                    echo "<option>$wholenames</option>";


                }
            } 
         } 
        else {
            echo "<option>No Names Present</option>";  
        }

RSM · Accepted Answer · 2011-08-15 12:12:58Z

3

To make it work, simply do this:

echo "<option>";
echo $wholenames;
echo "<option>";

or this:

echo "<option>$wholenames</option>";

or this:

echo '<option>'.$wholenames.'</option>';

All will work, just up to you which one you pick.

answered Aug 15, 2011 at 12:12

RSM

15.3k36 gold badges100 silver badges145 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Chris Over a year ago

Or echo '<option>'.$wholenames.'</option>';

Alan Hollis Over a year ago

or take out the array which doesn't look like it's needed. echo '<option>'.$row2[f_name].' '.$row2[s_name].'</option>';

J0HN · Accepted Answer · 2011-08-15 12:13:38Z

0

You shouldn't have " before <option> and after </option>

It should be something like

echo "<option>". echo $wholenames; echo "</option>";

Also, if $wholenames is an array, you'd better iterate over it:

foreach ($wholenames as $name){
    echo "<option>". echo $name; echo "</option>";
}

answered Aug 15, 2011 at 12:13

J0HN

27.1k5 gold badges59 silver badges88 bronze badges

Comments

Johann du Toit · Accepted Answer · 2011-08-15 12:20:54Z

0

Any text for options in a HTML SELECT box are written inside the tag. If you don't put your text between the <option> tags the browser will try to insert it to the select box's DOM.

So you could change your code to this:

echo '<option value="myvalue">"' . $wholenames . '"</option>';

Haven't actually tested this code.

Update if the Quotation mark was not meant to be in the output you would simply need to write:

echo '<option value="myvalue">' . $wholenames . '</option>';

In php you can use both " " and ' ' with strings.

edited Aug 15, 2011 at 12:20

answered Aug 15, 2011 at 12:14

Johann du Toit

2,6672 gold badges17 silver badges31 bronze badges

1 Comment

Johann du Toit Over a year ago

Where is the broken string? Are talking about PHP seeing it as a broken string or the HTML?

Collectives™ on Stack Overflow

Having trouble with echoing HTML in php script

3 Answers 3

2 Comments

Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

2 Comments

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related