I have been looking at other similar questions but didn't find the proper answer. $1 is the name of the array i want to loop over.
#!/bin/bash
for i in ${"$1"[@]}
do
echo "$i"
done
2 Answers
If I don't misunderstand your not very well written question, you are looking for bash indirection, which is available since bash, version 2.
Below a minimal example
#! /bin/bash
foo=( 1 2 3 4 )
bar=( 5 6 7 8 )
if [[ ( "$1" -ne foo && "$1" -ne bar ) ]];
then
echo "Usage: $0 <foo|bar>"
exit 1
fi
ambito="$1"[@] # here what you are looking for
for i in "${!ambito}"; # here the indirection
do
echo -n "$i "
done
echo ""
And you can call this indirection.sh scrit as:
$ ./indirection.sh foo
1 2 3 4
or
$ ./indirection.sh bar
5 6 7 8
This being said, using indirection may cause confusion. In most cases it could be replaced by associative arrays.
$1 is the first command line argument, not all of them. Probably what you are looking for is $@.
And to create an array holding them, something like:
ambito=($@)
4 Comments
n7rc
No, it is precisely about passing the first argument of the command line that corresponds to one of the arrays contained in hosts.sh. Thanks for your reply.
vgratian
well then the solution to your problem depends on what you mean by "corresponds".
vgratian
if
$1 holds the name of the array, you can write a switch statementn7rc
Thanks for your reply. I ask below what is my intention.
$1is always a scalar. There is no way that you can invoke a script in a way that this parameter becomes an array.$@would be (kind of) an array, but as a special variable, it does not act like an array in every respect.