Calling JavaScript sibling function inside parent function

Question

I’m struggling with this and I haven’t found anything conclusive about this.

How can I call the function y() inside the function z() without altering the code's structure?

I tried using this but it didn’t work.

function x(){

    function y(){
    console.log("sal y")
  }
  
  function z(){
    console.log("sal z");
    y()
  }
 
}

This is working. What is the issue? You just need to call x() somewhere and call z() somewhere inside it. — Omkar Kulkarni
– Omkar Kulkarni, Commented Jan 27, 2022 at 19:40

Rory O'Kane · Accepted Answer · 2022-01-27 19:39:58Z

2

Your code inside z calls y in the correct way – that’s not the problem. The reason you’re not seeing output in your snippet is that you’re never calling function z. If I edit function x to call z, and I edit the top level to call function x, it works.

function x() {
  function y() {
    console.log("sal y");
  }

  function z() {
    console.log("sal z");
    y();
  }
  
  z(); // added
}

x(); // added

answered Jan 27, 2022 at 19:39

Rory O'Kane

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