Python - convert binary string to little nibble hex string

Question

Input:

0000001101110010000000100000011110000000100000111000000111110010

Output should be:

302720700838182f

In perl I can do it like this:

unpack("h*", pack("B*", "0000001101110010000000100000011110000000100000111000000111110010"));

Your example doesn't make sense to me. Just look at the last 8 bits; how do you go from 11110010 to 82? Guessing at what you mean by "little nibble", 2f would make sense; — Tim Peters
– Tim Peters, Commented Mar 2, 2022 at 5:02

hobbs · Accepted Answer · 2022-03-02 05:51:17Z

1

"".join([ ("%02x" % int(x,2))[::-1] for x in re.findall(r'.{8}', bits) ])

I'm sure there's a nicer way, but it works: extract 8 bits at a time from the input, use int(..., 2) to parse them as binary, then format as hex, then swap the nibbles ([::-1]), then stick it all back together.

alternatively, if you find the use of re here ugly:

"".join([ ("%02x" % int(bits[i:i+8],2) )[::-1] for i in range(0, len(bits), 8) ])

answered Mar 2, 2022 at 5:51

hobbs

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