How to print output with spaces in between each number [duplicate]

Question

My code runs fine but I would like for each number to have a space between each number

string = input()
newstring = "".join(c for c in string if c.isalpha())
def alphabet(newstring):
    dict = {'a':'1','b':'2','c':'3','d':'4','e':'5','f':'6','g':'7','h':'8','i':'9','j':'10','k':'11','l':'12','m':'13','n':'14','o':'15','p':'16','q':'17','r':'18','s':'19','t':'20','u':'21','v':'22','w':'23','x':'24','y':'25','z':'26'}
    new = newstring.lower()
    for i in (new):
        if i in dict:
            new = new.replace(i, dict[i])
    return new
print(alphabet(newstring))

Blackgaurd · Accepted Answer · 2022-04-03 02:28:25Z

1

You can use keyword arguments in the print statement like this:

...
print(*alphabet(newstring), sep=" ")

answered Apr 3, 2022 at 2:28

Blackgaurd

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Comments

checked · Accepted Answer · 2022-04-03 02:23:16Z

0

Here you can add space to be appended with dict[i] like

new = new.replace(i, dict[i]+" ")

answered Apr 3, 2022 at 2:23

checked

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2 Comments

joshclark234 Over a year ago

The code grader says my output is wrong because an additional space is added after the last number. any suggestions on how to delete the final space?

checked Over a year ago

try adding .rstrip() in print like print(alphabet(newstring) .rstrip())

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