jquery, undefined variable problem, how to?

Question

i have this situation:

<div class="cont_picture">
<?php echo "<a id=\"mine_click\" href=\"#\" >a test</a>"; ?>
</div>
<div id="number"><?php echo $number; ?></div>

this will give me something like: a test 123456 (the link is as an example only)

then i have the jquery:

$('#mine_click').live('click', function() {
    var strtalentnum = $('#number').text();
    $('#mine').trigger('click');
})

and;

if($strtalentnum){
alert ($strtalentnum);
}

but the alert doesnt work.

Any ideas how to get this working? see jsfiddle

thanks

ShankarSangoli · Accepted Answer · 2011-09-01 16:56:32Z

1

You have defined strtalentnum inside #mine_click click event handler and try to access it outside the handler which is out of scope. If you want to access it outside the handler then define it in the outer scope or glbally.

Also the variable you are trying to alert begins with $. I think its a typo.

Working demo

var strtalentnum;

$('#mine_click').live('click', function() {
    strtalentnum = $('#number').text();
    $('#mine').trigger('click');
});

$('#mine').click(function(){
   if(strtalentnum){
       alert (strtalentnum);
   }
});

edited Sep 1, 2011 at 16:56

answered Sep 1, 2011 at 16:51

ShankarSangoli

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6 Comments

jondavidjohn Over a year ago

this will never trigger the alert, because when the if executes, it will always be undefined

jondavidjohn Over a year ago

@Shank do you not see the first comment? down voted because your original example didn't work, vengeful down voting is not very nice either...

ShankarSangoli Over a year ago

I didnt provide any example in my original answer. I added the demo later after editing. Aslo can you tell me anywhere mentioned in the question where is if($strtalentnum){ alert ($strtalentnum); } executed? I believe it is inside $('#mine').click handler.

jondavidjohn Over a year ago

it's not... but that's the problem that caused him to post the question... he wan'ts it to... if you don't think he ever wants to execute it why did you edit your answer to do so?

ShankarSangoli Over a year ago

Looking at $('#mine').trigger('click'); in the click handler made me do so.

|

akirk · Accepted Answer · 2011-09-01 16:54:26Z

1

Put the if inside the function() and beware that you are writing $strtalentnum but the variable is called strtalentnum

answered Sep 1, 2011 at 16:54

akirk

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