Get the Java version in specific format using bash

Question

My Java version is:

openjdk version "1.8.0_312"
OpenJDK Runtime Environment (build 1.8.0_312-b07)
OpenJDK 64-Bit Server VM (build 25.312-b07, mixed mode)

How can I get the Java version in below format using bash script: 1.8.0

I tried multiple options like java -version 2>&1 | head -n 1 | cut -d'"' -f2, but I'm unable to get the desired output.

There may be useful information about that in stackoverflow.com/q/7334754/10871900 (although that's mainly about the major version) — dan1st
– dan1st, Commented Jul 18, 2022 at 8:36
@criztovyl I want to check if exact matching version i.e "1.8.0" exists on my machine or not. I referred many stackoverflow content however unable to get the desired result. — user15566016
– user15566016, Commented Jul 18, 2022 at 8:37
do you need to extract the version or is it enough to know it is that version? — criztovyl
– criztovyl, Commented Jul 18, 2022 at 8:41

criztovyl · Accepted Answer · 2022-07-18 10:32:33Z

3

To check for a string (your expected version), you can use grep:

if java -version 2>&1 | head -n 1 | grep --fixed-strings '"1.8.0'
then echo expected version
else echo unexpected version
fi

Note the --fixed-strings (short -F), otherwise grep treats . as a RegEx and it will match any character. Thx Gorodon for pointing that out! I also added the leading " quote so it will not match 11.8.0.

edited Jul 18, 2022 at 10:32

answered Jul 18, 2022 at 8:49

criztovyl

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2 Comments

Gordon Davisson Over a year ago

grep treats its argument as a regular expression, meaning that "." will match any character. It also only looks for a match somewhere in a line, meaning it'll match substrings. These mean it could match things that're radically different from what you'd expect, like "11.8.0" or "1.850.5".

criztovyl Over a year ago

Argh, true! I'll add -F

Ed Morton · Accepted Answer · 2022-07-18 11:27:16Z

1

$ IFS='"_' read -r _ ver _ < <(java -version 2>&1)
$ echo "$ver"
1.8.0

answered Jul 18, 2022 at 11:27

Ed Morton

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Comments

0xh3xa · Accepted Answer · 2022-07-18 08:51:56Z

0

You can try this one

java --version | head -n1 |cut -d " " -f1,2

output

openjdk 8.0

answered Jul 18, 2022 at 8:51

0xh3xa

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sinkmanu · Accepted Answer · 2022-07-18 09:24:32Z

0

You can use grep (or egrep) to print matching patterns:

java --version | head -n 1 | grep -Po '[[:digit:]]{1,3}\.[[:digit:]]{1,3}\.[[:digit:]]{1,3}'     
java --version | head -n 1 | egrep -o '[[:digit:]]{1,3}\.[[:digit:]]{1,3}\.[[:digit:]]{1,3}'

answered Jul 18, 2022 at 9:24

sinkmanu

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