How to get java version using single command in Windows command prompt?

Question

I need to fetch java version 1.6.0_26 from the below java -version output

java version "1.6.0_26"
Java(TM) SE Runtime Environment (build 1.6.0_26-b03)
Java HotSpot(TM) Client VM (build 20.1-b02, mixed mode, sharing)

Please help me getting 1.6.0_26

Note: I don't need power shell or any external programs

UPDATE

I came up with java -version 2>&1 | findstr /i "version" which give me below output

java version "1.6.0_22"

now even a java way of pattern matching or regex will work for me :)

Describe your end goal? Perhaps there is a better way. And isn't this the same question as stackoverflow.com/questions/5675459/… — Aravind Yarram
– Aravind Yarram, Commented Sep 30, 2011 at 6:19
@Pangea: the link gets javaversion using a batch file, I needed something through which I get javaversion 1.6.0_26 directly using a one liner, since I cannot deploy my batch file in customers machine — AabinGunz
– AabinGunz, Commented Sep 30, 2011 at 6:23
Why not just call for the java.version property in code and either use that directly or write it to a new blank line in the file? Otherwise I really can't see what Java (as a programming language) has to do with this. — Andrew Thompson
– Andrew Thompson, Commented Sep 30, 2011 at 8:25

score 4 · Accepted Answer · 2011-09-30 15:50:57Z

4

You can run the solution from the question Pangea linked to in a single line:

    
c:\>for /f "tokens=3" %g in ('java -version 2^>^&1 ^| findstr /i "version"') do @echo %g
"1.6.0_24"
c:\>for /f "tokens=3" %g in ('java -version 2^>^&1 ^| findstr /i "version"') do ( @set v=%g & @echo %v:~1,8% )
1.6.0_24

I just checked and it seems my second example only works with Windows7, the following works for me on Windows XP (so it should work on Windows7 as well)

for /f "tokens=3" %g in ('java -version 2^>^&1 ^| findstr /i "version"') do ( @echo %~g )

edited Sep 30, 2011 at 15:50

answered Sep 30, 2011 at 8:28

user330315

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5 Comments

AabinGunz Over a year ago

I know its too much to ask but still " cannot be removed?

user330315 Over a year ago

See my edit. However this assumes a certain length of the response which might not always work well.

user330315 Over a year ago

Hmm, works for me. Do you have the "Command Extensions" enabled? They are by default and that's what enables the %v:~1,8% syntax

AabinGunz Over a year ago

I have no idea what you just said :P what do you mean by "Command Extensions" Also I need to go with whatever comes by default

user330315 Over a year ago

@AbhishekSimon: see my edit. It seems the first syntax only works under Windows7

Muhammad Aamir Ali · Accepted Answer · 2015-01-21 06:40:38Z

3

you can do it from single line from command promt C:>java -version

answered Jan 21, 2015 at 6:40

Muhammad Aamir Ali

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Comments

Kris · Accepted Answer · 2011-09-30 06:59:18Z

2

You can try:

java -version 2>&1 | awk '/version/ {print $3}' | egrep -o '[^\"]*'

answered Sep 30, 2011 at 6:59

Kris

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3 Comments

Kris Over a year ago

Bollocs, haven't noticed that earlier

AabinGunz Over a year ago

you might want to delete your answer, as people may down vote

Barend Over a year ago

Actually, this answer is perfectly valid with a Windows port of the UNIX utils.

npocmaka · Accepted Answer · 2014-04-26 05:19:25Z

for /f tokens^=2-5^ delims^=.-_^" %j in ('java -fullversion 2^>^&1') do @set "jver=%j%k%l%m"

This will store the java version into jver variable and as integer And you can use it for comparisons .E.G

if %jver% LSS 16000 echo not supported version

.You can use more major version by removing %k and %l and %m.This command prompt version.

For .bat use this:

@echo off
PATH %PATH%;%JAVA_HOME%\bin\
for /f tokens^=2-5^ delims^=.-_^" %%j in ('java -fullversion 2^>^&1') do set "jver=%%j%%k%%l%%m"

According to my tests this is the fastest way to get the java version from bat (as it uses only internal commands and not external ones as FIND,FINDSTR and does not use GOTO which also can slow the script). Some JDK vendors does not support -fullversion switch or their implementation is not the same as this one provided by Oracle (better avoid them).

AabinGunz · Accepted Answer · 2011-09-30 08:28:04Z

0

I wrote the below function to fetch java version 1.6.0_26

String regexMatch(String myInput, String myRegex)
{
String ResultString
Pattern regex
Matcher regexMatcher

regex = Pattern.compile(myRegex, Pattern.DOTALL);

regexMatcher = regex.matcher(myInput);

List<String> matchList = new ArrayList<String>();
while (regexMatcher.find()) {
    matchList.add(regexMatcher.group());
}

for(int i=0;i<matchList.size();i++)
{
    myInput=myInput.replaceAll( matchList[i], '')
}
return myInput;
}

and call

rs=regexMatch(rs,"[a-zA-Z\"]+")

where rs="java version \"1.6.0_26\""

answered Sep 30, 2011 at 8:28

AabinGunz

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Comments

equiman · Accepted Answer · 2017-05-12 17:40:23Z

0

Based on @a_horse_with_no_name but detecting first if command exists.

where java > nul
if %ERRORLEVEL% neq 0 (
    set java_v="Command not found"
) else (
    for /f "tokens=3" %%g in ('java -version 2^>^&1 ^| findstr /i "version"') do set java_v=%%g
)
echo  Java: %java_v:~1,8%

answered May 12, 2017 at 17:40

equiman

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