Make array value variable (PHP)

Question

Say I want to echo an array but I want to make the value in the array I echo variable, how would I do this?

Below is kind of an explanation of what I won't to do but it isn't the correct syntax.

$number = 0;
echo myArray[$number];

Don't edit the question to fix the problem, it won't make sense if anyone ever references it in the future. — Chad Birch
– Chad Birch, Commented Apr 9, 2009 at 23:18
This is another piece of code that if they tried to actually run it, would throw an error, which might at least have put them onto the right track to fix it. — Alister Bulman
– Alister Bulman, Commented Apr 9, 2009 at 23:30

Paolo Bergantino · Accepted Answer · 2009-04-09 23:11:02Z

12

I'm not sure what you mean. What you have isn't working because you're missing a $ in myArray:

$myArray = array('hi','hiya','hello','gday');
$index = 2;
echo $myArray[$index]; // prints hello
$index = 0;
echo $myArray[$index]; // prints hi

Unlike other languages, all PHP variable types are preceded by a dollar sign.

answered Apr 9, 2009 at 23:11

Paolo Bergantino

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Comments

uuɐɯǝʃǝs · Accepted Answer · 2009-04-09 23:22:32Z

4

Just to add more. Another type of array is associative array, where the element is determined using some identifier, usually string.

$arrayStates = array('NY' => 'New York', 'CA' => 'California');

To display the values, you can use:

echo $arrayStates['NY']; //prints New York

or, you can also use its numeric index

echo $arrayStates[1]; //prints California

To iterate all values of an array, use foreach or for.

foreach($arrayStates as $state) {
        echo $state;
}

Remember, if foreach is used on non-array, it will produce warning. So you may want to do:

if(is_array($arrayStates)) {
    foreach($arrayStates as $state) {
            echo $state;
    }
}

Hope that helps!

answered Apr 9, 2009 at 23:22

uuɐɯǝʃǝs

1 Comment

OIS Over a year ago

No, you can not get the second value from an array with a numeric number. You have to use the key, though type conversion applies so '1' is equal to 1 as a key.

Alister Bulman · Accepted Answer · 2009-04-09 23:11:40Z

2

You are nearly there:

$number = 0;
$myArray = array('a', 'b')
echo $myArray[$number];   // outputs 'a'

answered Apr 9, 2009 at 23:11

Alister Bulman

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Comments

score 1 · Accepted Answer · 2009-04-11 19:09:39Z

1

$myArray = array("one","two","three","four");
$arrSize=sizeof($myArray);

for ($number = 0; $number < $arrSize; $number++) {
echo "$myArray[$number] ";
}

// Output: one two three four

edited Apr 11, 2009 at 19:09

answered Apr 9, 2009 at 23:18

user36457

Comments

saw black · Accepted Answer · 2017-11-05 08:18:44Z

0

$myArray = array('hi','hiya','hello','gday');

for($count=0;$count<count($myArray);$count++)
{
  $SingleValue = $myArray[$count];
  $AllTogether = $AllTogether.",".$SingleValue;
}

answered Nov 5, 2017 at 8:18

saw black

1

1 Comment

dwjohnston Over a year ago

It would probably be helpful to add some notes explaining your answer.

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