Firebase - Dynamic Link not working with Android 12

Question

I am sending an authentication link to the user's email address using Android and Firebase. Everything works as expected with Android 9, 10, and 11, with both release and debug versions. However, when tapping on the authentication link on devices running Android 12, the browsers (I tried with several browsers) redirect to an error page "Invalid Dynamic Link, requested URL must be a parsable and complete DynamicLink, etc...", whereas the same link works on other devices. What am I missing?

Here's the code:

ActionCodeSettings actionCodeSettings =
            ActionCodeSettings.newBuilder()
                    .setUrl("https://appName.page.link")
                    .setHandleCodeInApp(true)
                    .setIOSBundleId("com.appName.ios")
                    .setAndroidPackageName(
                            "com.appName.android",
                            false, 
                            getResources().getString(R.string.min_version_android))
                    .build();

   
    FirebaseAuth auth = FirebaseAuth.getInstance();
    auth.sendSignInLinkToEmail(emailAddress, actionCodeSettings).addOnSuccessListener(new OnSuccessListener<Void>() {
        @Override
        public void onSuccess(Void unused) {
            Intent intent = new Intent(SignIn.this, CheckSignInInbox.class);
            startActivity(intent);
        }
    }).addOnFailureListener(new OnFailureListener() {
        @Override
        public void onFailure(@NonNull Exception e) {
            String msg = getTimestamp() + "Error in sendSignInLinkToEmail: " + e.getMessage();
            logErrorAndFirebaseCrash(SignIn.this, msg);
        }
    });

nibbana · Accepted Answer · 2022-09-13 09:15:21Z

3

I found the cause of the issue. In the manifest, in order to make it work with Android 12 as well, I had to include in my intent-filter android:autoVerify="true", as follows:

<intent-filter android:autoVerify="true">
     <action android:name="android.intent.action.VIEW" />

     <data
         android:host="domainname.page.link"
         android:scheme="https" />

         <category android:name="android.intent.category.BROWSABLE" />
         <category android:name="android.intent.category.DEFAULT" />
</intent-filter>

answered Sep 13, 2022 at 9:15

nibbana

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7 Comments

ezmegy Over a year ago

Saved my day! Had an older app (flutter v1.22) with Firebase passwordless sign-in that I needed to port to Android 12 and I just couldn't get the link to be opened in the app (instead in Play Store via the browser); this was the cause. Thanks!

nibbana Over a year ago

Glad to hear it. Don't hesitate to accept the answer then, tks

Fernando Luca De Tena Over a year ago

In case someone is facing this issue and cannot find the issue, in my case, the change is that before in the "intent-filter" the "android:scheme" part was at the beginning, not it has to be at the end. So from this: ``` <data android:scheme="https" android:host="example.link.com"/> ``` To this: ``` <data android:host="example.link.com" android:scheme="https"/> ´´´ Hope it saves someone an entire day ;)

Ahmet Yılmaz Over a year ago

@Himani Changed target sdk to 32 that solved for me.

Fcps Over a year ago

@Himani Add all sub domains host (long and short dynamic link) in the data tag in your intent filter declared in AndroidManifest.xml

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Fcps · Accepted Answer · 2023-07-10 14:22:20Z

0

If you target sdk 33 and still have the problem, check on firebase console your dynamic link details. You'll see there are different host for long and short dynamic link. Add both in your <data> in your <intent-filter> in your AndroidManifest.xml. It worked for me to add all sub domains in data tag.

answered Jul 10, 2023 at 14:22

Fcps

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