how do I initialise an array of pointers to int?

Question

this is annoying me....

Can anybody let me know how to initialise so I can call the function below with parameters.

// arr is typedef'ed to an array on integers

typedef int arr[];

// arr_ptr is a pointer to an array of integers

typedef arr *arr_ptr;

// two parameters, A & B are pointers to array // of integers and N the size of both the arrays

void F(arr_ptr A, arr_ptr B, size_t N)
{
    // array of pointers to int
}

How do I call F with parameters? N is obviously the length of A & B's array but I cant get a function call compiling ok.

You should mention which programming language your question is about. — Manfred
– Manfred, Commented Sep 17, 2022 at 17:35

Aniket Sinha · Accepted Answer · 2022-09-17 17:44:56Z

3

try

typedef *arr_ptr[arr.size()];

this should create an array of pointers

answered Sep 17, 2022 at 17:44

Aniket Sinha

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1 Comment

Thanks ! Umm...can't see where I mark this as answered so you get your credits. Where do I do that.