How to get a signed 32 bit integer from hex bytes without being 2's complement applied to it in java

Question

I have 4bytes of hex values directly without two's complement being applied to signed inetger. How do I get an int value from hex bytes using java.

Eugene Kuleshov · Accepted Answer · 2011-10-05 14:41:03Z

1

Doesn't this work?

int value = ((0xff & b4) < 24) | ((0xff & b3) < 16) | ((0xff & b2) < 8) | (0xff & b1);

answered Oct 5, 2011 at 14:41

Eugene Kuleshov

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Comments

pillingworth · Accepted Answer · 2011-10-05 14:42:08Z

0

Use a Long. You can't use an int as it's always signed and 4 bytes just won't fit.

    Long l = Long.parseLong("FFFFFFFF", 16);

answered Oct 5, 2011 at 14:42

pillingworth

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For a signed in, you can use int l = (int) Long.parseLong("FFFFFFFF", 16);