16 bit hex string to signed int in Java

Question

I have a string in Java representing a signed 16-bit value in HEX. This string can by anything from "0000" to "FFFF".

I use Integer.parseInt("FFFF",16) to convert it to an integer. However, this returns an unsigned value (65535).

I want it to return a signed value. In this particular example "FFFF" should return -1.

How can I achieve this? Since its a 16-bit value I thought of using Short.parseShort("FFFF",16) but that tells me that I am out of range. I guess parseShort() expects a negative sign.

Andreas Fester · Accepted Answer · 2013-03-04 13:46:06Z

16

You can cast the int returned from Integer.parseInt() to a short:

short s = (short) Integer.parseInt("FFFF",16);
System.out.println(s);

Result:

-1

answered Mar 4, 2013 at 13:46

Andreas Fester

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3 Comments

Rachael Over a year ago

@AndreasFester , why does this require further cast as short?

Andreas Fester Over a year ago

@Rachael Because the value returned by Integer.parseInt is still a (32 bit) int value - for 0xFFFF, that is 65535. By assigning it to a short, the upper 16 bits are effectively discarded and bit 15 is taken as the sign bit for the short value, resulting in -1 (all bits are 1). The cast is required to tell the compiler that this loss of bits is intended - without the cast, the compiler would complain about possible lossy conversion from int to short

Rachael Over a year ago

@AndreasFester thank you for that great explanation.

Evgeniy Dorofeev · Accepted Answer · 2013-03-04 13:46:08Z

2

try

int i = (short) Integer.parseInt("FFFF", 16);

answered Mar 4, 2013 at 13:46

Evgeniy Dorofeev

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