I am trying to write a simple shell-script that prints out the first parameter if there is one and prints "none" if it doesn't. The script is called test.sh
if [$1 = ""]
then
echo "none"
else
echo $1
fi
If I run the script without a parameter everything works. However if I run this command source test.sh -test, I get this error -bash: [test: command not found before the script continues on and correctly echos test. What am I doing wrong?
you need spaces before/after '[',']' chars, i.e.
if [ "$1" = "" ] ; then
#---^---------^ here
echo "none"
else
echo "$1"
fi
And you need to wrap your reference (really all references) to $1 with quotes as edited above.
After you fix that, you may also need to give a relative path to your script, i.e.
source ./test.sh -test
#------^^--- there
When you get a shell error message has you have here, it almost always helps to turn on shell debugging with set -vx before the lines that are causing your trouble, OR very near the top your script. Then you can see each line/block of code that is being executed, AND the value of the variables that the shell is using.
I hope this helps.
] too
