print PHP value in an array

Question

Hello I am trying to print a specific value from an array of objects. I am trying to get a value from an array name $allPhotos with a object's property of "nme"'s value.

This is what im trying: echo $allPhotos[0]["nme"];

this is what the array looks like:

var_dump($allPhotos);

array(2) {
  [0]=> object(Photo)#1 (10) { 
    ["product"]=> array(5) { 
      ["PKG1"]=> string(4) "6500" 
      ["PKG2"]=> string(4) "9500" 
      ["8x10"]=> string(4) "1500" 
      ["5x7"]=> string(3) "750" 
      ["4x6"]=> string(3) "300" 
    } 
    ["price"]=> NULL ["sku"]=> string(1) "1" 
    ["nme"]=> string(5) "test1" 
    ["dir"]=> string(51) "http://" 
    ["status"]=> string(1) "1" ["gallery"]=> string(16) "Church Directory"    
    ["galleryCover"]=> string(1) "0" 
    ["family"]=> string(0) "" 
    ["familyCover"]=> string(0) "" 
} 

[1]=> object(Photo)#2 (10) { 
  ["product"]=> array(5) { 
    ["PKG1"]=> string(4) "6500" 
    ["PKG2"]=> string(4) "9500" 
    ["8x10"]=> string(4) "1500" 
    ["5x7"]=> string(3) "750" 
    ["4x6"]=> string(3) "300" 
  } 
  ["price"]=> NULL 
  ["sku"]=> string(1) "2" 
  ["nme"]=> string(5) "test2" 
  ["dir"]=> string(51) "http://" 
  ["status"]=> string(1) "1" 
  ["gallery"]=> string(16) "Church Directory" 
  ["galleryCover"]=> string(1) "0" 
  ["family"]=> string(0) "" 
  ["familyCover"]=> string(0) "" 
 } 
}

Thanks in advance!

Have you tried echo $allPhotos[0]["nme"]; ?

Dave
– Dave

2011-10-29 05:24:37 +00:00
Commented Oct 29, 2011 at 5:24 — Dave
– Dave, Commented Oct 29, 2011 at 5:24

Tim · Accepted Answer · 2011-10-29 05:25:55Z

4

I believe echo $allPhotos[0]->nme; should work.

answered Oct 29, 2011 at 5:25

Tim

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3 Comments

Seralize Over a year ago

I believe so too. Have no experience with this sort of array indexing as I haven't needed it yet, though a simple Google search got me the same answer. Might also be a duplicate of this: link

user1019416 Over a year ago

Yep that's it, Thanks a lot. Just wondering why does $allPhotos[0]["nme"]; not work? is it because it is still in an object in the array?

Tim Over a year ago

The array is an array of objects. The object $allPhotos[0] is not an array, and so you have to use -> to access its properties. Think of it this way: $n = $allPhotos[0]; echo $n->nme;

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