Symfony2 - Multiple forms in one action

Question

I implemented a page to create an instance of an entity and a user related to this. My problem is to bind the request after the submit.

Now i have this :

$formA = $this->createForm(new \MyApp\ABundle\Form\AddObjectForm());
$formB = $this->createForm(new \MyApp\UserBundle\Form\AddUserForm());

if ($request->getMethod() == 'POST')
{
    $formA->bindRequest($request);
    $formB->bindRequest($request);

    if ($formA->isValid() && $formB->isValid())
    {
    }
    // ...
}

With formA and formB extends AbstractType. But, naturally, $formA->isValid() returns false. How can I do to "cut" the request for example ?

Elnur Abdurrakhimov · Accepted Answer · 2011-11-03 17:33:48Z

6

If your forms are related and need to be processed and validated at once, consider using embedded forms. Otherwise, use a separate action for each form.

If you need to provide a select field to choose a user from existing ones, consider using an entity type field.

answered Nov 3, 2011 at 17:33

Elnur Abdurrakhimov

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1 Comment

user1018146 Over a year ago

Thanks, embedded forms is just what i needed.

fray88 · Accepted Answer · 2013-02-17 15:46:54Z

5

I know that has been a long time since the answer, but maybe if someone is looking for it this could be helpfull.

I've got two forms: user_form and company_form, and the submit has take place in the same function of the controller. I can know wich form has been submit with the follow code:

    if ($request->getMethod() == 'POST') {

       $data = $request->request->all();

        if (isset($data['user_form'])) //This if means that the user_form has been submit.
        {

The company_form will pass through the else.

answered Feb 17, 2013 at 15:46

fray88

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