How do I do this in a .bat batch file:
if ("c:\program files\visualsvn server\bin\svnlook.exe" log -r2 d:\repositories\myrepo | findstr "~~DEPLOY~~" )
(
#dosomething
)
else
(
#dosomethingelse
)
now I receive an error log was unexpected at this time.
Use && and || to conditionally execute commands based on the success or failure of a previous command
"c:\program files\visualsvn server\bin\svnlook.exe" log -r2 d:\repositories\myrepo | findstr "~~DEPLOY~~" >nul && (
#do_Something_If_Success
) || (
#do_Something_Else_If_Failure
)
Try this instead:
setlocal enabledelayedexpansion
set found_deploy=0
for /f 'eol=; tokens=1 delims=' %%c in ('"c:\program files\visualsvnserver\bin\svnlook.exe" log -r2 d:\repositories\myrepo ^| findstr "~~DEPLOY~~"') do (
set found_deploy=1
)
if "!found_deploy!"=="1" (
@REM::do_something_based_on_finding_deploy
) else (
@REM::do_something_based_on_not_finding_deploy
)
dbenham's answer assemble an IF-THEN-ELSE that is both advanced and criptic. kikuchiyo's one is unnecessarily complicated.
This is a medium point between the previous two:
"c:\program files\visualsvn server\bin\svnlook.exe" log -r2 d:\repositories\myrepo | findstr "~~DEPLOY~~" >nul
if errorlevel 1 (
echo Deploy not found
) else (
echo Deploy found
)
