Wordpress PHP Syntax

Question

I'm trying to create a PHP 'if' statement that tells an image to display on certain pages in Wordpress. What I'm trying to do is shown below, but I think the syntax is incorrect.

I'm trying to say "If the page displayed equals 'about' or 'gallery' and that page is not 'services', go ahead and display the image.

Here's the section of code that you should be able to analyze and see where I went wrong:

<?php if(is_page('about' || 'gallery') && (is_page != 'services')) { ?>
 <li><img id="profile_pic" alt="DermaKare (Official Fan Page)" src="http://profile.ak.fbcdn.net/hprofile-ak-snc4/50556_123510051042639_3343345_n.jpg" class="photo img" /></li>
            <?php } ?>
            <?php if ( !function_exists('dynamic_sidebar') || !dynamic_sidebar("Banner") ) : ?>
        <?php /*?><p><a href='<?php bloginfo('siteurl')?>/wp-admin/widgets.php'>Widgetize this sidebar</a></p><?php */?>
            <?php endif; ?>

Thanks in advance for any help on this.....

I think it's just the first half of the code that needs to be looked at, not the bottom. — Rob Myrick
– Rob Myrick, Commented Dec 16, 2011 at 22:10

hakre · Accepted Answer · 2011-12-16 22:11:58Z

3

If a page is about or gallery then it never is services. So you can spare that not part.

Next to that you need to call the function twice:

if (is_page('about') || is_page('gallery'))
{
    # then
}

This should do it. Wrapped into your code this should look like:

<?php if  (is_page('about') || is_page('gallery')) { ?>

answered Dec 16, 2011 at 22:11

hakre

200k55 gold badges454 silver badges865 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

usoban · Accepted Answer · 2011-12-16 22:12:08Z

1

if ( ( is_page('about') || is_page('gallery') ) && !is_page('services') )

watch the brackets.

edit: and what @hakre said, if it's about or gallery, it never is services

answered Dec 16, 2011 at 22:12

usoban

5,47830 silver badges42 bronze badges

Comments

Michael Sazonov · Accepted Answer · 2011-12-16 22:15:22Z

0

<?php if( (is_page('about') || is_page('gallery') ) && (!is_page('services') ) {
 echo "<li><img id=\"profile_pic\" alt=\"DermaKare (Official Fan Page)\" src=\"http://profile.ak.fbcdn.net/hprofile-ak-snc4/50556_123510051042639_3343345_n.jpg\" class=\"photo img\" /></li>";
} ?>

this should work

answered Dec 16, 2011 at 22:15

Michael Sazonov

1,53311 silver badges21 bronze badges

3 Comments

Rob Myrick Over a year ago

Hi Mike, I tried it and it didn't work for some reason. I know your code makes sense, and I double checked how I'm identifying the page and it seems correct. Any other ideas? I could let you login if you want to look yourself.....let me know

Michael Sazonov Over a year ago

@RobMyrick It seems I forgot to close (!is_page('services') ). It should be (!is_page('services') ) ). Try it now

Rob Myrick Over a year ago

Mike I used your code intertwined with an answer below. thanks for your help

Collectives™ on Stack Overflow

Wordpress PHP Syntax

3 Answers 3

Comments

Comments

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related