I have run into a problem. My php class structure is as follows:
class CustomerDao{
...
var $lastid;
function insertUser($user)
{
...
$lastid = mysql_insert_id();
return 0;
}
function getCustId()
{
return $lastid;
}
}
When i use this class, it let me access $lastid varibale in first function "insertUser", but it throws an error when i use $lastid in second function. I have no idea how to resolve this problem. Please guide.
You're trying to access a class variable, which is done like this instead:
function getCustId() {
return $this->lastid;
}
If you want to change an object property, you want the this keyword:
$this->lastid = mysql_insert_id();
Reference: PHP Manual: Classes and objects
In your first function you are creating a new variable called $lastid which exists only within the scope of the function. In the second function this fails because there is no $lastid variable declared within this function.
To access a class member you use the notation $this->lastid.
class CustomerDao {
...
var $lastid;
function insertUser($user)
{
...
$this->lastid = mysql_insert_id();
return 0;
}
function getCustId()
{
return $this->lastid;
}
}
Your code sample should look this:
class CustomerDao{
...
var $lastid;
function insertUser($user)
{
...
$this->lastid = mysql_insert_id();
return 0;
}
function getCustId()
{
return $this->lastid;
}
}
You need to reference the class ($this) to access its $lastid property. So it should be $this->lastid;
to use a class variable inside the class use the $this keyword
so to use $lastid variable inside class use $this->lastid
What you want to do is this:
function insertUser($user) {
...
$this->lastid = mysql_insert_id();
return 0;
}
function getCustId() {
return $this->lastid;
}
Note the this-keyword. Your first function works, because you assign a new (local!) variable $lastid within your insertUser() function - but it has nothing to do with the class property $lastid.
