zip function in python

Question

In python I have:

    nameh.append([area, hitratio])
    nameh_sorted = sorted (nameh, key=lambda nameh: nameh[0])

I sorted the [area, hitratio] based on the alphabet of the name of the area. Then I want to zip the sorted "hitratio" with another list "u" into [u1, hitratio1], [u2, hitratio2]...but I don't know how to select the sorted hitratio in this case, the *nameh_sorted[1] is obviously wrong...

user = zip (u,*nameh_sorted[1])
user_sorted = sorted (user, key=lambda user: user[0])
x5, y5 = zip(*user_sorted)

Can anyone help? Many thanks

You don't need to provide a key function in this case -- the default is to sort lexicographically, so the first element is the primary search key by default. — Sven Marnach
– Sven Marnach, Commented Jan 13, 2012 at 16:13

Sven Marnach · Accepted Answer · 2012-01-13 16:12:29Z

2

user = zip(u, (hitratio for area, hitratio in nameh_sorted))

answered Jan 13, 2012 at 16:12

Sven Marnach

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Wesley · Accepted Answer · 2012-01-13 16:15:01Z

0

Try:

user = zip(u, [x[1] for x in nameh_sorted])

Is that what you want?

answered Jan 13, 2012 at 16:15

Wesley

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