Can I pass javascript variable to a PHP form?

Question

I'm using jcrop to crop my photos and need to send the current values along with my form submission. Is there an easy way to do this?

The JavaScript variable is this:

c = coords;
$.param(c)

Can I include this as a hidden field in my PHP form somehow?

<input type="hidden" name="coords" value=" ??? " />

user703016 · Accepted Answer · 2012-01-22 18:04:15Z

5

Of course you can:

<form onsubmit='document.getElementById("your-hidden-field-id").value = c.toString(); return true;'>
...
<input type="hidden" name="coords" id="your-hidden-field-id"/>
</form>

answered Jan 22, 2012 at 18:04

user703016

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4 Comments

Paul Over a year ago

I'm trying the follwoing but crop_coords is always empty: <form id="process_image_form" action="<?php echo $_SERVER['PHP_SELF'];?>" method="post" onsubmit='$("#crop_cords").val() = $.param(c).toString(); return true;'>

Paul Over a year ago

The value of $.param(c).toString() is valid.

user703016 Over a year ago

There are several things wrong in your code. First you probably mistyped crop_coords. Second, .val() is a getter, not a setter.

Paul Over a year ago

Cicada: That was it: $("#crop_cords").val($.param(c).toString()) worked! Thanks!

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