I'm using time.strptime to parse a string as a date, but the string does not have a year associated with it. How can I add the current year to the date object?
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2 Answers
import time, datetime
def currentyear(atime):
atime = tuple([datetime.datetime.now().year] + list(atime)[1:])
return time.localtime(time.mktime(atime))
newtime = time.strptime("19 Jan", "%d %b")
newtime = currentyear(newtime)
print newtime
Comments
>>> import datetime
>>> import time
>>> dt = time.strptime('12/31/' + str(datetime.datetime.now().year), '%d/%M/%Y')
>>> print dt
time.struct_time(tm_year=2012, tm_mon=1, tm_mday=12, tm_hour=0, tm_min=31, tm_sec=0, tm_wday=3, tm_yday=12, tm_isdst=-1)
This is far from the only way to do it.
