getting a stringArray resource with a string variable

Question

I am trying to get a stringArray resource with this code:

String continent = "europe";  
getResources().getStringArray(R.array.continent);

If I type R.array.europe, its ok, but I want this to be dynamic, so I'm looking for a way to use my string variable here..

This is probably a simple java problem, but I'm quite a noob both in java and android programming, and I didn't find the answer..

Thanks in advance;

edit: so here is my complete onCreate Method, did I do something wrong?

protected void onCreate(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onCreate(savedInstanceState);
        setContentView(R.layout.second);
       String continent = (String) getIntent().getExtras().getString("continent");

       int holderint = getResources().getIdentifier(continent, "Array",
               this.getPackageName());

       String[] items = getResources().getStringArray(holderint);


        setListAdapter(new ArrayAdapter<String>(this, 
                android.R.layout.simple_list_item_1, 
                items));

    }

I'm not sure about the defPackage part though...

Richard Lewin · Accepted Answer · 2012-02-11 17:49:39Z

2

With the name of the resource created dynamically in code, you could look at using

getResources().getIdentifier(String name, String defType, String defPackage);

This will return an id for a specified resource.

answered Feb 11, 2012 at 17:49

Richard Lewin

1,8702 gold badges19 silver badges26 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Vilrouge Over a year ago

thank you very much, it looks like what I need, I will try it and let you know

bschultz · Accepted Answer · 2012-02-11 17:33:26Z

1

You could create a String variable containing "R.array." and append it with your continent object.

answered Feb 11, 2012 at 17:33

bschultz

4,2641 gold badge27 silver badges33 bronze badges

3 Comments

Vilrouge Over a year ago

but my continent object is a string, putting R.array.europe as a string will not do... i need to be able to get the resource from a string...

bschultz Over a year ago

I'm not sure I understand what you're saying. From what you said in your question, it sounds like continent is dynamic, so you want to pull the string resource based on continent. So if you append "R.array." with whichever continent is selected, you should get "R.array.selectedContinent" as your result.

Vilrouge Over a year ago

exactly, but that gives me a string, and the getStringArray method seems to be looking for an integer

alice_silver_man · Accepted Answer · 2013-07-02 18:17:01Z

0

Here is an alternate approach that I find easy to use:

int resourceId = R.array.class.getField(yourStringVariable).getInt(null); String[] yourStringArray = getResources().getStringArray(resourceId);

Note that yourStringVariable is in the form "europe", not "R.array.europe".

answered Jul 2, 2013 at 18:17

alice_silver_man

4125 silver badges19 bronze badges

Comments

Hamlet Kraskian · Accepted Answer · 2014-05-03 15:53:00Z

0

I had the same problem. Using

getResources().getIdentifier(String name, String defType, String defPackage);

with

name : should be the resource name inside the file. ( Avoid adding R.array. in the begining of your resource name, because there is no resource with name R.array.yourname ) deftype: Should be "array". defPackage: this.getPackageName()

The problem has been solved

edited May 3, 2014 at 15:53

answered Feb 18, 2013 at 11:54

Hamlet Kraskian

80110 silver badges11 bronze badges

Comments

Saurabh Padwekar · Accepted Answer · 2017-11-14 09:09:09Z

0

You can get the array resource id using this :

Sting name = "resource_array_name";
int resourceId= getResources().getIdentifier(name, "array",this.getPackageName());
String[] items = getResources().getStringArray(resourceId);

answered Nov 14, 2017 at 9:09

Saurabh Padwekar

4,0841 gold badge37 silver badges37 bronze badges

Collectives™ on Stack Overflow

getting a stringArray resource with a string variable

5 Answers 5

1 Comment

3 Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

5 Answers 5

1 Comment

3 Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related