Skip keys in array without values in a foreach loop

Question

I have a normal one dimensional array, let's call it $myarray, with several keys ranging from [0] to [34]. Some keys could be empty though.

Suppose I want to use such array in a foreach loop

 $i = 1;
 $choices = array(array('text' => ' ', 'value' => ' '));
 foreach ( $myarray as $item ) :
      $count = $i++; 
      $choices[] = array('text' => $count, 'value' => $count, 'price' => $item);
 endforeach;

I'd wish to skip in this foreach loop all the empty keys, therefore the other array I'm building here ($choices) could have a smaller amount of rows than $myarray. At the same time, though, as you see, I count the loops because I need an increasing number as value of one of the keys of the new array being built. The count should be progressive (1..2..3..4...).

thanks

Do you mean if one of the values is empty? Keys/indices cannot be empty in an array. — Josh
– Josh, Commented Feb 19, 2012 at 6:41
I don't see any empty values in your sample data. I see values containing spaces. — mickmackusa
– mickmackusa ♦, Commented Apr 3 at 20:53

Mike B · Accepted Answer · 2012-02-19 06:39:53Z

7

array_filter() will remove empty elements from an array

You can also use continue within a loop to skip the rest of the loop structure and move to the next item:

$array = array('foo', '', 'bar');

foreach($array as $value) {
  if (empty($value)) {
    continue;
  }

  echo $value . PHP_EOL;
}

// foo
// bar

answered Feb 19, 2012 at 6:39

Mike B

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