Replacing with Dynamic variable in preg_replace

Question

I'm trying the following code:

$t = '12<-- AB_C -->';
$AB_C = 'abc';
echo preg_replace('/\<-- ([A-Z_]+) --\>/', "$$1", $t);

I want to get "12abc" , but it outputs: 12$AB_C , so, it not recognize the replacement as dynamic variable. Is it any way to use the matched word in preg_replace() as a variable, or dynamic variable?

Edit:

For those who look for a solution to this problem, the '/e' flag, which evalates the replacement, solved the problem, and returns the results i want, using:

preg_replace('/\<-- ([A-Z_]+) --\>/e', "$$1", $t);

mathematical.coffee · Accepted Answer · 2012-02-20 06:17:50Z

1

Could you use preg_replace_callback?

It's like preg_replace, but with a callback function that takes an array $matches where $matches[0] is the entire match, $matches[1] is the first capturing group, etc.

Perhaps something like (sorry, not tested):

 preg_replace_callback(
        '/\<-- ([A-Z_]+) --\>/',
        create_function(
            '$matches',
            'return $$matches[1];' // attempt to retrieve value of $AB_C
        ),
        $t
    );

answered Feb 20, 2012 at 6:17

mathematical.coffee

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