How can i do the following:
I have a string
something#12
I need a regex that will get last two numbers from the string in range from 0 to 19. Note that nothing should be returned if the number after # is greater than 19, i need to ignore letters and special symbols either.
I have tried the following:
([0-9]{1}$)|([0-1]{1}[0-9]{1}$)
but it return last one or two numbers if i have a value greater than 19.
Just add the # before the digit:
#([0-9]{1}$)|([0-1]{1}[0-9]{1}$)
or simpler:
#[01]?\d$
I think you want something like:
/\D[0-1]?\d$/g
The \D will match any non-digit, \d will match any number and you want to optionally (?) allow 0 or 1 in front.
text#100 i will get last two zeros. I need to reduce everything that is not in 0..19 range.you have to set the character before as a non number or a #, someething like
[^0-9]([0-9]{1}$)|([0-1]{1}[0-9]{1}$)
function getThatThing(x) {
var match = /#([0-9]|[01][0-9])$/.exec("input#1");
if (match) {
return match[1];
} else {
return null;
}
}
