Create objects without causing a stack overflow error?

Question

So, I have my main class that calls private Secondary secondary = new Secondary(); when it runs. In the Secondary class, at the top I have code that says private Main main = new Main();.

How will I be able to use all of the methods and variables from the Secondary class and vice versa without causing a stack overflow error?

Note: they are not in the constructor

Your question doesn't make much sense: stack overflow errors are caused by calling too many nested methods, not by creating objects. — Wyzard
– Wyzard, Commented Nov 2, 2012 at 22:46
@Wyzard: It makes perfect sense - initializing a Secondary requires initializing a new Main, which requires initializing a new Secondary etc. It's recursive construction, rather than recursive method calls. — Jon Skeet
– Jon Skeet, Commented Nov 2, 2012 at 22:51
@JonSkeet, only if the calls are in the constructor, which the question doesn't specify, though it seems like a plausible interpretation. I'd assumed that the first sentence was referring to code in a static main() method. — Wyzard
– Wyzard, Commented Nov 2, 2012 at 22:59
@Wyzard: Those are clearly field declarations (otherwise private would be invalid), with variable initializers. — Jon Skeet
– Jon Skeet, Commented Nov 2, 2012 at 23:10

rgettman · Accepted Answer · 2012-11-02 22:47:55Z

2

Your Main class is creating a Secondary instance, which is creating a Main instance..., and this is causing the stack overflow error.

I think you just want the objects to refer to each other, so don't create the other class's new instance in the constructor. Declare references as instance variables, and use setter methods to store existing references to objects of the other type.

answered Nov 2, 2012 at 22:47

rgettman

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Bohemian · Accepted Answer · 2012-11-02 23:29:04Z

0

You could use the builder pattern to handle safe (non-recursive) initialization of your instance fields (via setters).

answered Nov 2, 2012 at 23:29

Bohemian♦

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