Cannot sort array with randomly generated numbers

Question

I am having trouble getting the array to sort after the random numbers are generated in the array. I think the array is being sorted before all the numbers are assigned. I have tried nesting another for loop inside of the main one also, but I either get the same result or an endless loop of random numbers.

public static void main(String[] args) {
    int[] anArray;
    anArray = new int[10000];
    Random generator= new Random();

    for(int i=0; i<10000; i++){
       anArray [i]= (generator.nextInt(98)+1);
       java.util.Arrays.sort(anArray);
       System.out.println(anArray[i];
    }
 }

assylias · Accepted Answer · 2013-01-29 23:16:02Z

3

You need to take java.util.Arrays.sort(anArray); outside of the loop, or you will sort at each step and the i-th element will not be what you just added:

for(int i=0; i<10000; i++){
   anArray [i]= (generator.nextInt(98)+1);
}
java.util.Arrays.sort(anArray);
System.out.println(Arrays.toString(anArray));

answered Jan 29, 2013 at 23:16

assylias

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