Sorting array of random numbers

Question

Hey guys looking for some help with my ArrayTester class... The array is supposed to 1.create a 20 element int array and populates it with random elements in the range 20 through 65 (both inclusive). -I Believe I have already done this.

2.Use the java.util.Random class with a seed of 2621 to generate repeatable output for the data. -I have also already done this

3.The tester class should then test each of these methods(mean, median, mode, max, min, standard divination) -this is where I'm having trouble, I already have the code for the mean, mode, max, min, and standard divination.. the problem I'm having is with the median as i would like to sort my array in the tester class before having it called by my main Class.

Is there any way to do this?

Here is my code:

public class ArrayTest
{
    public static void main(String [] args)
    {
        int[] numbers;
        numbers = new int [20];
        Random rand = new Random(2621); 
        int maxRange = 65;
        int minRange = 20;

        for(int i=0; i<20; i++)
        {
            numbers[i] = rand.nextInt(maxRange - minRange + 1) + minRange;
            //checks to see if printing out ocrrectly
            System.out.println(numbers[i]);

        }
    }
}

Standard "deviation." "Divination" involves slaughtering small animals and looking at their entrails. Arrays.sort — O. Jones
– O. Jones, Commented Feb 13, 2013 at 1:10

iTech · Accepted Answer · 2013-02-13 01:09:15Z

5

You can use Arrays.sort(numbers);

answered Feb 13, 2013 at 1:09

iTech

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4 Comments

user1905170 Over a year ago

I know that but if I put it right before the system.out.println I keep getting an error

iTech Over a year ago

You have to do this after the loop, otherwise your array will not be fully populated.

user1905170 Over a year ago

I'm having trouble even with that, as of right now when I put the Arrays.sort(numbers); outside the for loop nothing changes when I outprint the array (the numbers are still printing out, they're just not sorted) This made me believe that I had to also move my System.out.println(numbers[i]) outside the for loop as well. However when I do this I get an error saying that it cannot find the variable [i]

iTech Over a year ago

You will need 2 loops, fist to generate the random numbers which you already have and then callArrays.sort and then another loop to print the array again which will be now sorted

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