How to receive python's array in function

Question

How do I receive an array (like numpy ones) into a function? Let's say the array a = [[2],[3]] and the function f. Tuples works like this:

def f((a ,b)):
    print a * b

f((2,3))

But how is it with arrays?

def f(#here):
    print a*b

f([[2],[3]])

As a side note, the form of the first function is a SyntaxError in python3.x. I would advise moving away from using that construct. — mgilson
– mgilson, Commented May 21, 2013 at 1:56
Thanks for the advice! I've been far from python's news hehe. — Alejandro Sazo
– Alejandro Sazo, Commented May 21, 2013 at 1:58

Blender · Accepted Answer · 2013-05-21 01:50:26Z

1

Tuple unpacking in function arguments has been removed from Python 3, so I suggest you stop using it.

Lists can be unpacked just like tuples:

def f(arg):
    [[a], [b]] = arg

    return a * b

Or as a tuple:

((x,), (y,)) = a

But I would just use indexes:

return arg[0][0] * arg[1][0]

answered May 21, 2013 at 1:50

Blender

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1 Comment

Alejandro Sazo Over a year ago

Thanks for the unpacking advice. @mgilson wrote it below the question but both were helpful. I use a and b because the goal is to be clear in the code (a and b has their meaning in a context).

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