JavaScript SyntaxError in php print

Question

I'm getting this error in java console: "SyntaxError: unterminated regular expression literal"

I really don't understand it. Below is my code, if someone could point out what am I missing I would be forever gratefull.

PHP Code:

print '
<script type="text/javascript">
function fakeUpload() {
    $("#fakeupload").val(this.files && this.files.length ? this.files[0].name : this.value.replace(/^C:\\fakepath\\/i, ""));
}
</script>';

Thanks.

ComFreek · Accepted Answer · 2013-09-22 17:55:12Z

2

The two slashes (\\) become one slash in the output of PHP (\). You have to write four slashes (\\\\).

Let's see the output of your current code:

this.value.replace(/^C:\fakepath\/i, "");

The last backslash escapes the Regex terminator (the forward slash), therefore the regular expression terminal is unterminated.

Here is the output of the updated code:

this.value.replace(/^C:\\fakepath\\/i, "");
---------------------------------^^
escapes                           |
----------------------------------|

The last backslash won't affect anything because it is escaped by the backslash before it.

answered Sep 22, 2013 at 17:55

ComFreek

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Comments

Shankar Narayana Damodaran · Accepted Answer · 2013-09-22 17:54:46Z

1

You missed an escape slash here

this.value.replace(/^C:\\fakepath\\//i, ""));
                                    ^

Try like this

<?php
print '
<script type="text/javascript">
function fakeUpload() {
    $("#fakeupload").val(this.files && this.files.length ? this.files[0].name : this.value.replace(/^C:\\fakepath\\//i, ""));
}
</script>';

answered Sep 22, 2013 at 17:54

Shankar Narayana Damodaran

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